0=16x^2+18x-55

Solution for 0=16x^2+18x-55 equation:

0=16x^2+18x-55

We move all terms to the left:

0-(16x^2+18x-55)=0

We add all the numbers together, and all the variables

-(16x^2+18x-55)=0

We get rid of parentheses

-16x^2-18x+55=0

a = -16; b = -18; c = +55;
Δ = b2-4ac
Δ = -182-4·(-16)·55
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3844}=62$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-62}{2*-16}=\frac{-44}{-32}
=1+3/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+62}{2*-16}=\frac{80}{-32}
=-2+1/2
$